(2w-1)(2-w)=0

Solution for (2w-1)(2-w)=0 equation:

(2w-1)(2-w)=0

We add all the numbers together, and all the variables

(2w-1)(-1w+2)=0

We multiply parentheses ..

(-2w^2+4w+w-2)=0

We get rid of parentheses

-2w^2+4w+w-2=0

We add all the numbers together, and all the variables

-2w^2+5w-2=0

a = -2; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·(-2)·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3}{2*-2}=\frac{-8}{-4}
=+2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3}{2*-2}=\frac{-2}{-4}
=1/2
$