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(2w-3)(w)=(2w+1)(w+2)-66
We move all terms to the left:
(2w-3)(w)-((2w+1)(w+2)-66)=0
We multiply parentheses
2w^2-3w-((2w+1)(w+2)-66)=0
We multiply parentheses ..
2w^2-((+2w^2+4w+w+2)-66)-3w=0
We calculate terms in parentheses: -((+2w^2+4w+w+2)-66), so:We add all the numbers together, and all the variables
(+2w^2+4w+w+2)-66
We get rid of parentheses
2w^2+4w+w+2-66
We add all the numbers together, and all the variables
2w^2+5w-64
Back to the equation:
-(2w^2+5w-64)
2w^2-3w-(2w^2+5w-64)=0
We get rid of parentheses
2w^2-2w^2-3w-5w+64=0
We add all the numbers together, and all the variables
-8w+64=0
We move all terms containing w to the left, all other terms to the right
-8w=-64
w=-64/-8
w=+8
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