(2w-3)*w=35

Solution for (2w-3)*w=35 equation:

(2w-3)*w=35

We move all terms to the left:

(2w-3)*w-(35)=0

We multiply parentheses

2w^2-3w-35=0

a = 2; b = -3; c = -35;
Δ = b2-4ac
Δ = -32-4·2·(-35)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-17}{2*2}=\frac{-14}{4}
=-3+1/2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+17}{2*2}=\frac{20}{4}
=5
$