(2w-4)(-1/2)=-12

Solution for (2w-4)(-1/2)=-12 equation:

(2w-4)(-1/2)=-12

We move all terms to the left:

(2w-4)(-1/2)-(-12)=0

We add all the numbers together, and all the variables

(2w-4)(-1/2)+12=0

We multiply parentheses ..

(-2w^2-4*-1/2)+12=0

We multiply all the terms by the denominator


(-2w^2-4*-1+12*2)=0

We get rid of parentheses

-2w^2-1-4*+12*2=0

We add all the numbers together, and all the variables

-2w^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{-4}=0$