(2w-8)(6w+1)=0

Solution for (2w-8)(6w+1)=0 equation:

(2w-8)(6w+1)=0

We multiply parentheses ..

(+12w^2+2w-48w-8)=0

We get rid of parentheses

12w^2+2w-48w-8=0

We add all the numbers together, and all the variables

12w^2-46w-8=0

a = 12; b = -46; c = -8;
Δ = b2-4ac
Δ = -462-4·12·(-8)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-50}{2*12}=\frac{-4}{24}
=-1/6
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+50}{2*12}=\frac{96}{24}
=4
$