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(2x)(1/2x)=180
We move all terms to the left:
(2x)(1/2x)-(180)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x(+1/2x)-180=0
We multiply parentheses
2x^2-180=0
a = 2; b = 0; c = -180;
Δ = b2-4ac
Δ = 02-4·2·(-180)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{10}}{2*2}=\frac{0-12\sqrt{10}}{4} =-\frac{12\sqrt{10}}{4} =-3\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{10}}{2*2}=\frac{0+12\sqrt{10}}{4} =\frac{12\sqrt{10}}{4} =3\sqrt{10} $
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