(2x)(3x-10)=50

Solution for (2x)(3x-10)=50 equation:

(2x)(3x-10)=50

We move all terms to the left:

(2x)(3x-10)-(50)=0

We multiply parentheses

6x^2-20x-50=0

a = 6; b = -20; c = -50;
Δ = b2-4ac
Δ = -202-4·6·(-50)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*6}=\frac{-20}{12}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*6}=\frac{60}{12}
=5
$