(2x)(x)+75=(2x-5)(x+5)

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Solution for (2x)(x)+75=(2x-5)(x+5) equation: 



(2x)(x)+75=(2x-5)(x+5)

We move all terms to the left:

(2x)(x)+75-((2x-5)(x+5))=0

We multiply parentheses ..

-((+2x^2+10x-5x-25))+2xx+75=0



We calculate terms in parentheses: -((+2x^2+10x-5x-25)), so:

(+2x^2+10x-5x-25)

We get rid of parentheses

2x^2+10x-5x-25

We add all the numbers together, and all the variables

2x^2+5x-25

Back to the equation:

-(2x^2+5x-25)



We get rid of parentheses

-2x^2-5x+2xx+25+75=0

We add all the numbers together, and all the variables

-2x^2-5x+2xx+100=0

We move all terms containing x to the left, all other terms to the right

-2x^2-5x+2xx=-100

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