(2x)*x=288

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Solution for (2x)*x=288 equation:



(2x)*x=288
We move all terms to the left:
(2x)*x-(288)=0
Wy multiply elements
2x^2-288=0
a = 2; b = 0; c = -288;
Δ = b2-4ac
Δ = 02-4·2·(-288)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*2}=\frac{-48}{4} =-12 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*2}=\frac{48}{4} =12 $

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