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(2x)+(1/2x)+90=180
We move all terms to the left:
(2x)+(1/2x)+90-(180)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2x+(+1/2x)+90-180=0
We add all the numbers together, and all the variables
2x+(+1/2x)-90=0
We get rid of parentheses
2x+1/2x-90=0
We multiply all the terms by the denominator
2x*2x-90*2x+1=0
Wy multiply elements
4x^2-180x+1=0
a = 4; b = -180; c = +1;
Δ = b2-4ac
Δ = -1802-4·4·1
Δ = 32384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32384}=\sqrt{64*506}=\sqrt{64}*\sqrt{506}=8\sqrt{506}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-8\sqrt{506}}{2*4}=\frac{180-8\sqrt{506}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+8\sqrt{506}}{2*4}=\frac{180+8\sqrt{506}}{8} $
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