(2x)+(2x)+(3x+3)+(3x+3)=146

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Solution for (2x)+(2x)+(3x+3)+(3x+3)=146 equation:


Simplifying
(2x) + (2x) + (3x + 3) + (3x + 3) = 146

Reorder the terms:
(2x) + (2x) + (3 + 3x) + (3x + 3) = 146

Remove parenthesis around (3 + 3x)
(2x) + (2x) + 3 + 3x + (3x + 3) = 146

Reorder the terms:
(2x) + (2x) + 3 + 3x + (3 + 3x) = 146

Remove parenthesis around (3 + 3x)
(2x) + (2x) + 3 + 3x + 3 + 3x = 146

Reorder the terms:
3 + 3 + (2x) + (2x) + 3x + 3x = 146

Combine like terms: 3 + 3 = 6
6 + (2x) + (2x) + 3x + 3x = 146

Combine like terms: (2x) + (2x) = 4x
6 + 4x + 3x + 3x = 146

Combine like terms: 4x + 3x = 7x
6 + 7x + 3x = 146

Combine like terms: 7x + 3x = 10x
6 + 10x = 146

Solving
6 + 10x = 146

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 10x = 146 + -6

Combine like terms: 6 + -6 = 0
0 + 10x = 146 + -6
10x = 146 + -6

Combine like terms: 146 + -6 = 140
10x = 140

Divide each side by '10'.
x = 14

Simplifying
x = 14

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