(2x)+(3x+1)+(3x-5)=180

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Solution for (2x)+(3x+1)+(3x-5)=180 equation:



(2x)+(3x+1)+(3x-5)=180
We move all terms to the left:
(2x)+(3x+1)+(3x-5)-(180)=0
We get rid of parentheses
2x+3x+3x+1-5-180=0
We add all the numbers together, and all the variables
8x-184=0
We move all terms containing x to the left, all other terms to the right
8x=184
x=184/8
x=23

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