(2x)+(3x-1)=(137-x)

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Solution for (2x)+(3x-1)=(137-x) equation:



(2x)+(3x-1)=(137-x)
We move all terms to the left:
(2x)+(3x-1)-((137-x))=0
We add all the numbers together, and all the variables
2x+(3x-1)-((-1x+137))=0
We get rid of parentheses
2x+3x-((-1x+137))-1=0
We calculate terms in parentheses: -((-1x+137)), so:
(-1x+137)
We get rid of parentheses
-1x+137
Back to the equation:
-(-1x+137)
We add all the numbers together, and all the variables
5x-(-1x+137)-1=0
We get rid of parentheses
5x+1x-137-1=0
We add all the numbers together, and all the variables
6x-138=0
We move all terms containing x to the left, all other terms to the right
6x=138
x=138/6
x=23

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