(2x)+(x+2)+(x-4)=66

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Solution for (2x)+(x+2)+(x-4)=66 equation: 



(2x)+(x+2)+(x-4)=66

We move all terms to the left:

(2x)+(x+2)+(x-4)-(66)=0

We get rid of parentheses

2x+x+x+2-4-66=0

We add all the numbers together, and all the variables

4x-68=0

We move all terms containing x to the left, all other terms to the right

4x=68

x=68/4

x=17

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