(2x)+(x+20)=122

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Solution for (2x)+(x+20)=122 equation: 



(2x)+(x+20)=122

We move all terms to the left:

(2x)+(x+20)-(122)=0

We get rid of parentheses

2x+x+20-122=0

We add all the numbers together, and all the variables

3x-102=0

We move all terms containing x to the left, all other terms to the right

3x=102

x=102/3

x=34

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