(2x)/(x+1)=(2x-1)/x

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Solution for (2x)/(x+1)=(2x-1)/x equation: 


D( x )

x = 0

x+1 = 0

x = 0

x = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:0) U (0:+oo)

(2*x)/(x+1) = (2*x-1)/x // - (2*x-1)/x

(2*x)/(x+1)-((2*x-1)/x) = 0

(2*x)/(x+1)+(-1*(2*x-1))/x = 0

(2*x*x)/(x*(x+1))+(-1*(2*x-1)*(x+1))/(x*(x+1)) = 0

2*x*x-1*(2*x-1)*(x+1) = 0

1-x = 0

(1-x)/(x*(x+1)) = 0

(1-x)/(x*(x+1)) = 0 // * x*(x+1)

1-x = 0

1-x = 0 // - 1

-x = -1 // * -1

x = 1

x = 1

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