(2x)/(x+1)=5-(2)/(x+1)

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Solution for (2x)/(x+1)=5-(2)/(x+1) equation: 



(2x)/(x+1)=5-(2)/(x+1)

We move all terms to the left:

(2x)/(x+1)-(5-(2)/(x+1))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x+1))!=0

x∈R



We calculate fractions


4x^2/((x+1)*(x+1)))+(-(-2*(x+6))/((x+1)*(x+1)))=0



We calculate terms in parentheses: -(-2*(x+6))/((x+1)*(x+1))), so:

-2*(x+6))/((x+1)*(x+1))

We multiply all the terms by the denominator


-2*(x+6))

We multiply parentheses

-2x-

We add all the numbers together, and all the variables

-2x

Back to the equation:

-(-2x)



We get rid of parentheses

4x^2/((x+1)*(x+1)))+(+2x=0

We multiply all the terms by the denominator


4x^2+2x*((x+1)*(x+1)))+(=0

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