(2x)/3=(x/6)+1

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Solution for (2x)/3=(x/6)+1 equation: 



(2x)/3=(x/6)+1

We move all terms to the left:

(2x)/3-((x/6)+1)=0

We add all the numbers together, and all the variables

2x/3-((+x/6)+1)=0

We calculate fractions


12x^2/()+(-((+x*3)/()=0



We calculate terms in parentheses: +(-((+x*3)/(), so:

-((+x*3)/(

We multiply all the terms by the denominator


-((+x*3)



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(+x*3





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(+x*3





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(+x*3





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Back to the equation:

+(-((+x*3))



We multiply all the terms by the denominator


12x^2+((-((+x*3)))*()=0



We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





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(-((+x*3)))*(





We calculate terms in parentheses: +((-((+x*3)))*(), so:

(-((+x*3)))*(





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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