(2x)/7-3=2

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Solution for (2x)/7-3=2 equation: 



(2x)/7-3=2

We move all terms to the left:

(2x)/7-3-(2)=0

We add all the numbers together, and all the variables

2x/7-5=0

We multiply all the terms by the denominator


2x-5*7=0

We add all the numbers together, and all the variables

2x-35=0

We move all terms containing x to the left, all other terms to the right

2x=35

x=35/2

x=17+1/2

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