(2x)2-3x-7=5

Solution for (2x)2-3x-7=5 equation:

(2x)2-3x-7=5

We move all terms to the left:

(2x)2-3x-7-(5)=0

We add all the numbers together, and all the variables

2x^2-3x-12=0

a = 2; b = -3; c = -12;
Δ = b2-4ac
Δ = -32-4·2·(-12)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{105}}{2*2}=\frac{3-\sqrt{105}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{105}}{2*2}=\frac{3+\sqrt{105}}{4}
$