(2x)2=22x2

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Solution for (2x)2=22x2 equation: 



(2x)2=22x^2

We move all terms to the left:

(2x)2-(22x^2)=0

determiningTheFunctionDomain
-22x^2+2x2=0

We add all the numbers together, and all the variables

-20x^2=0

a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-40}=0$

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