(2x)=0.5(10x+-21)

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Solution for (2x)=0.5(10x+-21) equation: 



(2x)=0.5(10x+-21)

We move all terms to the left:

(2x)-(0.5(10x+-21))=0

We add all the numbers together, and all the variables

2x-(0.5(10x-21))=0



We calculate terms in parentheses: -(0.5(10x-21)), so:

0.5(10x-21)

We multiply parentheses

5x-10.5

Back to the equation:

-(5x-10.5)



We get rid of parentheses

2x-5x+10.5=0

We add all the numbers together, and all the variables

-3x+10.5=0

We move all terms containing x to the left, all other terms to the right

-3x=-10.5

x=-10.5/-3

x=3+1/2

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