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(2x)x(2)=(3x)-(9/5)
We move all terms to the left:
(2x)x(2)-((3x)-(9/5))=0
We add all the numbers together, and all the variables
2xx2-(3x-(+9/5))=0
We multiply all the terms by the denominator
2xx2*5))-(3x-(+9=0
Wy multiply elements
10x^2+9=0
a = 10; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·10·9
Δ = -360
Delta is less than zero, so there is no solution for the equation
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