(2x*2x)-5x=0

Solution for (2x*2x)-5x=0 equation:

(2x*2x)-5x=0

We add all the numbers together, and all the variables

(+2x*2x)-5x=0

We add all the numbers together, and all the variables

-5x+(+2x*2x)=0

We get rid of parentheses

-5x+2x*2x=0

Wy multiply elements

4x^2-5x=0

a = 4; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·4·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*4}=\frac{10}{8}
=1+1/4
$