(2x*3x)=62

Solution for (2x*3x)=62 equation:

(2x*3x)=62

We move all terms to the left:

(2x*3x)-(62)=0

We add all the numbers together, and all the variables

(+2x*3x)-62=0

We get rid of parentheses

2x*3x-62=0

Wy multiply elements

6x^2-62=0

a = 6; b = 0; c = -62;
Δ = b2-4ac
Δ = 02-4·6·(-62)
Δ = 1488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1488}=\sqrt{16*93}=\sqrt{16}*\sqrt{93}=4\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{93}}{2*6}=\frac{0-4\sqrt{93}}{12}
=-\frac{4\sqrt{93}}{12}
=-\frac{\sqrt{93}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{93}}{2*6}=\frac{0+4\sqrt{93}}{12}
=\frac{4\sqrt{93}}{12}
=\frac{\sqrt{93}}{3}
$