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(2x*3x)=62
We move all terms to the left:
(2x*3x)-(62)=0
We add all the numbers together, and all the variables
(+2x*3x)-62=0
We get rid of parentheses
2x*3x-62=0
Wy multiply elements
6x^2-62=0
a = 6; b = 0; c = -62;
Δ = b2-4ac
Δ = 02-4·6·(-62)
Δ = 1488
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1488}=\sqrt{16*93}=\sqrt{16}*\sqrt{93}=4\sqrt{93}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{93}}{2*6}=\frac{0-4\sqrt{93}}{12} =-\frac{4\sqrt{93}}{12} =-\frac{\sqrt{93}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{93}}{2*6}=\frac{0+4\sqrt{93}}{12} =\frac{4\sqrt{93}}{12} =\frac{\sqrt{93}}{3} $
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