(2x*x-8x+6)=(x*x+x-2)

Solution for (2x*x-8x+6)=(x*x+x-2) equation:

(2x*x-8x+6)=(x*x+x-2)

We move all terms to the left:

(2x*x-8x+6)-((x*x+x-2))=0

We add all the numbers together, and all the variables

(-8x+2x*x+6)-((x+x*x-2))=0

We get rid of parentheses

-8x+2x*x-((x+x*x-2))+6=0


We calculate terms in parentheses: -((x+x*x-2)), so:

(x+x*x-2)

We get rid of parentheses

x+x*x-2

Wy multiply elements

x^2+x-2

Back to the equation:

-(x^2+x-2)


Wy multiply elements

2x^2-8x-(x^2+x-2)+6=0

We get rid of parentheses

2x^2-x^2-8x-x+2+6=0

We add all the numbers together, and all the variables

x^2-9x+8=0

a = 1; b = -9; c = +8;
Δ = b2-4ac
Δ = -92-4·1·8
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-7}{2*1}=\frac{2}{2}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+7}{2*1}=\frac{16}{2}
=8
$