(2x+(x+20))-4=38

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Solution for (2x+(x+20))-4=38 equation: 



(2x+(x+20))-4=38

We move all terms to the left:

(2x+(x+20))-4-(38)=0

We add all the numbers together, and all the variables

(2x+(x+20))-42=0



We calculate terms in parentheses: +(2x+(x+20)), so:

2x+(x+20)

We get rid of parentheses

2x+x+20

We add all the numbers together, and all the variables

3x+20

Back to the equation:

+(3x+20)



We get rid of parentheses

3x+20-42=0

We add all the numbers together, and all the variables

3x-22=0

We move all terms containing x to the left, all other terms to the right

3x=22

x=22/3

x=7+1/3

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