(2x+)+(3x-10)=70

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Solution for (2x+)+(3x-10)=70 equation: 



(2x+)+(3x-10)=70

We move all terms to the left:

(2x+)+(3x-10)-(70)=0

We add all the numbers together, and all the variables

(+2x)+(3x-10)-70=0

We get rid of parentheses

2x+3x-10-70=0

We add all the numbers together, and all the variables

5x-80=0

We move all terms containing x to the left, all other terms to the right

5x=80

x=80/5

x=16

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