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(2x+-5)(x+7)=4x+10
We move all terms to the left:
(2x+-5)(x+7)-(4x+10)=0
We add all the numbers together, and all the variables
(2x-5)(x+7)-(4x+10)=0
We get rid of parentheses
(2x-5)(x+7)-4x-10=0
We multiply parentheses ..
(+2x^2+14x-5x-35)-4x-10=0
We get rid of parentheses
2x^2+14x-5x-4x-35-10=0
We add all the numbers together, and all the variables
2x^2+5x-45=0
a = 2; b = 5; c = -45;
Δ = b2-4ac
Δ = 52-4·2·(-45)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{385}}{2*2}=\frac{-5-\sqrt{385}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{385}}{2*2}=\frac{-5+\sqrt{385}}{4} $
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