(2x+1)(2x+3)=4x(x-3)

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Solution for (2x+1)(2x+3)=4x(x-3) equation: 



(2x+1)(2x+3)=4x(x-3)

We move all terms to the left:

(2x+1)(2x+3)-(4x(x-3))=0

We multiply parentheses ..

(+4x^2+6x+2x+3)-(4x(x-3))=0



We calculate terms in parentheses: -(4x(x-3)), so:

4x(x-3)

We multiply parentheses

4x^2-12x

Back to the equation:

-(4x^2-12x)



We get rid of parentheses

4x^2-4x^2+6x+2x+12x+3=0

We add all the numbers together, and all the variables

20x+3=0

We move all terms containing x to the left, all other terms to the right

20x=-3

x=-3/20

x=-3/20

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