(2x+1)(2x-1)=35

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Solution for (2x+1)(2x-1)=35 equation:



(2x+1)(2x-1)=35
We move all terms to the left:
(2x+1)(2x-1)-(35)=0
We use the square of the difference formula
4x^2-1-35=0
We add all the numbers together, and all the variables
4x^2-36=0
a = 4; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·4·(-36)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*4}=\frac{-24}{8} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*4}=\frac{24}{8} =3 $

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