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(2x+1)(2x-2)=0
We multiply parentheses ..
(+4x^2-4x+2x-2)=0
We get rid of parentheses
4x^2-4x+2x-2=0
We add all the numbers together, and all the variables
4x^2-2x-2=0
a = 4; b = -2; c = -2;
Δ = b2-4ac
Δ = -22-4·4·(-2)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*4}=\frac{-4}{8} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*4}=\frac{8}{8} =1 $
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