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(2x+1)(2x-6)=0
We multiply parentheses ..
(+4x^2-12x+2x-6)=0
We get rid of parentheses
4x^2-12x+2x-6=0
We add all the numbers together, and all the variables
4x^2-10x-6=0
a = 4; b = -10; c = -6;
Δ = b2-4ac
Δ = -102-4·4·(-6)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-14}{2*4}=\frac{-4}{8} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+14}{2*4}=\frac{24}{8} =3 $
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