(2x+1)(3-x)+1=(5-x)2x-1)+3x

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Solution for (2x+1)(3-x)+1=(5-x)2x-1)+3x equation: 



(2x+1)(3-x)+1=(5-x)2x-1)+3x

We move all terms to the left:

(2x+1)(3-x)+1-((5-x)2x-1)+3x)=0

We add all the numbers together, and all the variables

(2x+1)(-1x+3)-((-1x+5)2x-1)+3x)+1=0

We multiply parentheses ..

(-2x^2+6x-1x+3)-((-1x+5)2x-1)+3x)+1=0



We calculate terms in parentheses: -((-1x+5)2x-1), so:

(-1x+5)2x-1

We multiply parentheses

-2x^2+10x-1

Back to the equation:

-(-2x^2+10x-1)



We get rid of parentheses

-2x^2+2x^2+6x-1x-10x+3x)+1+3+1=0

We add all the numbers together, and all the variables

-5x+3x)+1+3+1=0

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