(2x+1)(3x+1)(5x+1)(30x+1)=10.

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Solution for (2x+1)(3x+1)(5x+1)(30x+1)=10. equation: 



(2x+1)(3x+1)(5x+1)(30x+1)=10.

We move all terms to the left:

(2x+1)(3x+1)(5x+1)(30x+1)-(10.)=0

We add all the numbers together, and all the variables

(2x+1)(3x+1)(5x+1)(30x+1)-10=0

We multiply parentheses ..

(+6x^2+2x+3x+1)(5x+1)(30x+1)-10=0

We multiply parentheses ..

(+6x^2+2x+3x+1)(+150x^2+5x+30x+1)-10=0

We move all terms containing x to the left, all other terms to the right

(+6x^2+2x+3x+1)(+150x^2+5x+30x+1)=10

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