(2x+1)(3x+1)=6x(x+1

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Solution for (2x+1)(3x+1)=6x(x+1 equation: 



(2x+1)(3x+1)=6x(x+1

We move all terms to the left:

(2x+1)(3x+1)-(6x(x+1)=0

We multiply parentheses ..

(+6x^2+2x+3x+1)-(6x(x+1)=0



We calculate terms in parentheses: -(6x(x+1), so:

6x(x+1



We get rid of parentheses

6x^2+2x+3x-(6x(x+1)+1=0

We add all the numbers together, and all the variables

6x^2+5x-(6x(x+1)+1=0

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