(2x+1)(3x+10)(8/9x+10)=180

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Solution for (2x+1)(3x+10)(8/9x+10)=180 equation: 



(2x+1)(3x+10)(8/9x+10)=180

We move all terms to the left:

(2x+1)(3x+10)(8/9x+10)-(180)=0



Domain of the equation: 9x+10)!=0

x∈R



We multiply parentheses ..

(+6x^2+20x+3x+10)(8/9x+10)-180=0

We multiply all the terms by the denominator


(+6x^2+20x+3x+10)(8-180*9x+10)=0

We add all the numbers together, and all the variables

(+6x^2+20x+3x+10)(-180*9x+18)=0

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