(2x+1)(3x+10)=180

Solution for (2x+1)(3x+10)=180 equation:

(2x+1)(3x+10)=180

We move all terms to the left:

(2x+1)(3x+10)-(180)=0

We multiply parentheses ..

(+6x^2+20x+3x+10)-180=0

We get rid of parentheses

6x^2+20x+3x+10-180=0

We add all the numbers together, and all the variables

6x^2+23x-170=0

a = 6; b = 23; c = -170;
Δ = b2-4ac
Δ = 232-4·6·(-170)
Δ = 4609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{4609}}{2*6}=\frac{-23-\sqrt{4609}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{4609}}{2*6}=\frac{-23+\sqrt{4609}}{12}
$