If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x+1)(3x+2)=50
We move all terms to the left:
(2x+1)(3x+2)-(50)=0
We multiply parentheses ..
(+6x^2+4x+3x+2)-50=0
We get rid of parentheses
6x^2+4x+3x+2-50=0
We add all the numbers together, and all the variables
6x^2+7x-48=0
a = 6; b = 7; c = -48;
Δ = b2-4ac
Δ = 72-4·6·(-48)
Δ = 1201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1201}}{2*6}=\frac{-7-\sqrt{1201}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1201}}{2*6}=\frac{-7+\sqrt{1201}}{12} $
| 2a−a=17 | | 9x-(4x+4)=7x-14 | | 5x−2x=15 | | 5+2x-25=80 | | 2^x^2-x=4 | | 15h+5h=20 | | -90=6(4x+5) | | 3|2a-5|=21 | | 8^(3-4x)=(2^-9x) | | y=17(4+10)-8(10) | | 8^3-4x=2^-9x | | (4x-3)^2/3-2=23 | | y=8+3y | | 2(15+q)=30+ | | y+3=10y+1 | | 2.56=2r | | 18=6+3h | | r-8=-24 | | (5^(2x-8))*25=1 | | 18.4=3.4x-2 | | 51.2=4r | | x+-9=1 | | 3(n+7)=3n+ | | 7z-4*(z-8)=0 | | -8(3-3x)=-192 | | 4v+9=19-v | | x+66+33=180 | | 40*12+x*32=(x+40)*16 | | -16+m=-24 | | 5+r/10=3 | | 7n-39=6(7n-2)2 | | 5^(2x-8)=1/25 |