(2x+1)(3x-1)=(6x+5)(x+1)

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Solution for (2x+1)(3x-1)=(6x+5)(x+1) equation: 



(2x+1)(3x-1)=(6x+5)(x+1)

We move all terms to the left:

(2x+1)(3x-1)-((6x+5)(x+1))=0

We multiply parentheses ..

(+6x^2-2x+3x-1)-((6x+5)(x+1))=0



We calculate terms in parentheses: -((6x+5)(x+1)), so:

(6x+5)(x+1)

We multiply parentheses ..

(+6x^2+6x+5x+5)

We get rid of parentheses

6x^2+6x+5x+5

We add all the numbers together, and all the variables

6x^2+11x+5

Back to the equation:

-(6x^2+11x+5)



We get rid of parentheses

6x^2-6x^2-2x+3x-11x-1-5=0

We add all the numbers together, and all the variables

-10x-6=0

We move all terms containing x to the left, all other terms to the right

-10x=6

x=6/-10

x=-3/5

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