(2x+1)(5x+2)=(2x+2)(x-2)

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Solution for (2x+1)(5x+2)=(2x+2)(x-2) equation: 



(2x+1)(5x+2)=(2x+2)(x-2)

We move all terms to the left:

(2x+1)(5x+2)-((2x+2)(x-2))=0

We multiply parentheses ..

(+10x^2+4x+5x+2)-((2x+2)(x-2))=0



We calculate terms in parentheses: -((2x+2)(x-2)), so:

(2x+2)(x-2)

We multiply parentheses ..

(+2x^2-4x+2x-4)

We get rid of parentheses

2x^2-4x+2x-4

We add all the numbers together, and all the variables

2x^2-2x-4

Back to the equation:

-(2x^2-2x-4)



We get rid of parentheses

10x^2-2x^2+4x+5x+2x+2+4=0

We add all the numbers together, and all the variables

8x^2+11x+6=0

a = 8; b = 11; c = +6;
Δ = b2-4ac
Δ = 112-4·8·6
Δ = -71
Delta is less than zero, so there is no solution for the equation

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