(2x+1)(x+1)=60

Solution for (2x+1)(x+1)=60 equation:

(2x+1)(x+1)=60

We move all terms to the left:

(2x+1)(x+1)-(60)=0

We multiply parentheses ..

(+2x^2+2x+x+1)-60=0

We get rid of parentheses

2x^2+2x+x+1-60=0

We add all the numbers together, and all the variables

2x^2+3x-59=0

a = 2; b = 3; c = -59;
Δ = b2-4ac
Δ = 32-4·2·(-59)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{481}}{2*2}=\frac{-3-\sqrt{481}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{481}}{2*2}=\frac{-3+\sqrt{481}}{4}
$