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(2x+1)(x+11)=0
We multiply parentheses ..
(+2x^2+22x+x+11)=0
We get rid of parentheses
2x^2+22x+x+11=0
We add all the numbers together, and all the variables
2x^2+23x+11=0
a = 2; b = 23; c = +11;
Δ = b2-4ac
Δ = 232-4·2·11
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-21}{2*2}=\frac{-44}{4} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+21}{2*2}=\frac{-2}{4} =-1/2 $
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