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(2x+1)(x+14)=90
We move all terms to the left:
(2x+1)(x+14)-(90)=0
We multiply parentheses ..
(+2x^2+28x+x+14)-90=0
We get rid of parentheses
2x^2+28x+x+14-90=0
We add all the numbers together, and all the variables
2x^2+29x-76=0
a = 2; b = 29; c = -76;
Δ = b2-4ac
Δ = 292-4·2·(-76)
Δ = 1449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1449}=\sqrt{9*161}=\sqrt{9}*\sqrt{161}=3\sqrt{161}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-3\sqrt{161}}{2*2}=\frac{-29-3\sqrt{161}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+3\sqrt{161}}{2*2}=\frac{-29+3\sqrt{161}}{4} $
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