(2x+1)(x+2)=

Solution for (2x+1)(x+2)= equation:

Simplifying
(2x + 1)(x + 2) = 0

Reorder the terms:
(1 + 2x)(x + 2) = 0

Reorder the terms:
(1 + 2x)(2 + x) = 0

Multiply (1 + 2x) * (2 + x)
(1(2 + x) + 2x * (2 + x)) = 0
((2 * 1 + x * 1) + 2x * (2 + x)) = 0
((2 + 1x) + 2x * (2 + x)) = 0
(2 + 1x + (2 * 2x + x * 2x)) = 0
(2 + 1x + (4x + 2x2)) = 0

Combine like terms: 1x + 4x = 5x
(2 + 5x + 2x2) = 0

Solving
2 + 5x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(2 + x)(1 + 2x) = 0

Subproblem 1
Set the factor '(2 + x)' equal to zero and attempt to solve:

Simplifying
2 + x = 0

Solving
2 + x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + x = 0 + -2
x = 0 + -2

Combine like terms: 0 + -2 = -2
x = -2

Simplifying
x = -2
Subproblem 2
Set the factor '(1 + 2x)' equal to zero and attempt to solve:

Simplifying
1 + 2x = 0

Solving
1 + 2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2x = 0 + -1
2x = 0 + -1

Combine like terms: 0 + -1 = -1
2x = -1

Divide each side by '2'.
x = -0.5

Simplifying
x = -0.5
Solution
x = {-2, -0.5}