(2x+1)(x+3)=7x+11

Solution for (2x+1)(x+3)=7x+11 equation:

Simplifying
(2x + 1)(x + 3) = 7x + 11

Reorder the terms:
(1 + 2x)(x + 3) = 7x + 11

Reorder the terms:
(1 + 2x)(3 + x) = 7x + 11

Multiply (1 + 2x) * (3 + x)
(1(3 + x) + 2x * (3 + x)) = 7x + 11
((3 * 1 + x * 1) + 2x * (3 + x)) = 7x + 11
((3 + 1x) + 2x * (3 + x)) = 7x + 11
(3 + 1x + (3 * 2x + x * 2x)) = 7x + 11
(3 + 1x + (6x + 2x2)) = 7x + 11

Combine like terms: 1x + 6x = 7x
(3 + 7x + 2x2) = 7x + 11

Reorder the terms:
3 + 7x + 2x2 = 11 + 7x

Add '-7x' to each side of the equation.
3 + 7x + -7x + 2x2 = 11 + 7x + -7x

Combine like terms: 7x + -7x = 0
3 + 0 + 2x2 = 11 + 7x + -7x
3 + 2x2 = 11 + 7x + -7x

Combine like terms: 7x + -7x = 0
3 + 2x2 = 11 + 0
3 + 2x2 = 11

Solving
3 + 2x2 = 11

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2x2 = 11 + -3

Combine like terms: 3 + -3 = 0
0 + 2x2 = 11 + -3
2x2 = 11 + -3

Combine like terms: 11 + -3 = 8
2x2 = 8

Divide each side by '2'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}