(2x+1)(x+4)=0

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Solution for (2x+1)(x+4)=0 equation:


Simplifying
(2x + 1)(x + 4) = 0

Reorder the terms:
(1 + 2x)(x + 4) = 0

Reorder the terms:
(1 + 2x)(4 + x) = 0

Multiply (1 + 2x) * (4 + x)
(1(4 + x) + 2x * (4 + x)) = 0
((4 * 1 + x * 1) + 2x * (4 + x)) = 0
((4 + 1x) + 2x * (4 + x)) = 0
(4 + 1x + (4 * 2x + x * 2x)) = 0
(4 + 1x + (8x + 2x2)) = 0

Combine like terms: 1x + 8x = 9x
(4 + 9x + 2x2) = 0

Solving
4 + 9x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(4 + x)(1 + 2x) = 0

Subproblem 1

Set the factor '(4 + x)' equal to zero and attempt to solve: Simplifying 4 + x = 0 Solving 4 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + x = 0 + -4 x = 0 + -4 Combine like terms: 0 + -4 = -4 x = -4 Simplifying x = -4

Subproblem 2

Set the factor '(1 + 2x)' equal to zero and attempt to solve: Simplifying 1 + 2x = 0 Solving 1 + 2x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2x = 0 + -1 2x = 0 + -1 Combine like terms: 0 + -1 = -1 2x = -1 Divide each side by '2'. x = -0.5 Simplifying x = -0.5

Solution

x = {-4, -0.5}

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