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(2x+1)(x+9)=(2x+1)(x+9)
We move all terms to the left:
(2x+1)(x+9)-((2x+1)(x+9))=0
We multiply parentheses ..
(+2x^2+18x+x+9)-((+2x^2+18x+x+9))=0
We calculate terms in parentheses: -((+2x^2+18x+x+9)), so:We get rid of parentheses
(+2x^2+18x+x+9)
We get rid of parentheses
2x^2+18x+x+9
We add all the numbers together, and all the variables
2x^2+19x+9
Back to the equation:
-(2x^2+19x+9)
2x^2-2x^2+18x+x-19x+9-9=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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