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(2x+1)(x-1)-2x(x+2)(x-3)=12
We move all terms to the left:
(2x+1)(x-1)-2x(x+2)(x-3)-(12)=0
We multiply parentheses ..
(+2x^2-2x+x-1)-2x(x+2)(x-3)-12=0
We get rid of parentheses
2x^2-2x+x-2x(x+2)(x-3)-1-12=0
We multiply parentheses ..
2x^2-2x(+x^2-3x+2x-6)-2x+x-1-12=0
We add all the numbers together, and all the variables
2x^2-2x(+x^2-3x+2x-6)-1x-13=0
We multiply parentheses
2x^2-2x^3+6x^2-4x^2+12x-1x-13=0
We do not support expression: x^3
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