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(2x+1)(x-1)=-16-8
We move all terms to the left:
(2x+1)(x-1)-(-16-8)=0
We add all the numbers together, and all the variables
(2x+1)(x-1)-(-24)=0
We add all the numbers together, and all the variables
(2x+1)(x-1)+24=0
We multiply parentheses ..
(+2x^2-2x+x-1)+24=0
We get rid of parentheses
2x^2-2x+x-1+24=0
We add all the numbers together, and all the variables
2x^2-1x+23=0
a = 2; b = -1; c = +23;
Δ = b2-4ac
Δ = -12-4·2·23
Δ = -183
Delta is less than zero, so there is no solution for the equation
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